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If 2x = –1 + √3i, then the value of (1 – x^2 + x)^6 – (1 – x + x^2)^6 is (A) 32

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If 2x = –1 + √3i, then the value of (1 – x2 + x)6 – (1 – x + x2)6 is

(A) 32

(B) – 64

(C) 64 

(D) 0

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Correct option (D) 0

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1 answer
(-√3i)^2 = (A) 3 (B) 3i (C) -3 (D) -3i
asked Apr 12 in Mathematics by Bhagvad (45.2k points)

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