Question

A 3-digit number has, from left to right, the digits a, b and c with a > c. When the number with the digits reversed is subtracted from the original number, the unit’s digit in the difference is 4. The next two digits, from right to left, are 

(A) 5 and 9 

(B) 9 and 5 

(C) 5 and 4 

(D) 4 and 5

Answer 1

Correct option (B)

Explanation:

N = abc (let) ; a > c 

New number N' = cba 

Difference of digits at unit place = 4 

⇒ 10 + c – a = 4 

⇒ a – c = 6 

then middle digit = 9 and first digit = a – 1 – c = 5 

∴ then difference is 594