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Derive the expression for magnetic force in a current carrying conductor. F = i(l × B) 

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Consider a rod of a uniform cross-sectional area A and length l. Let n be the number density of charge carriers(free electrons) in it. 

Then the total number of mobile charge carriers in it is = nAl. Assume that these charge carriers are under motion with a drift velocity, vd. 

In the F = (n A l) q vd × B; here q is the charge of each charge carrier. presence of an external magnetic field B, the force on these charge carriers is 

But current density j = n q vd

F =  j A l × B 

But, j A = I, the electric current in the conductor, then 

∴ F = I l x B 

i.e. F = (I l B sinθ) 

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