**Correct option (A) area of quadrilateral ACBQ can be 100 sq. units**

**Explanation:**

Clearly, the point lies on 7x - y = 5

Also, centre of the circle must lie on the bisectors of the lines x + y + 13 = 0 and 7x - y - 5 = 0 given by

Let (h,k) be the centre of the circle, then h -3k = 35 ..... (1) and 3h + k +15 = 0 ..... (2)

Clearly CA is perpendicular AQ

Therefore area of quadrilateral ACBQ

units = 100 sq. units. Hence (A)