Correct option : (2) 100 days
Explanation:
Since the initial value of radiation is 32 times the permissible level we have to find t after which the activity drops to 1/32 of its initial value which implies that we must have
Since the half life is 20 days, the lab will be safe for use after 5 half–lives i.e., t = 20×5 = 100 days