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The following polynomial of order n is called Hermite polynomial: 

H"n − 2ξH'n + 2n Hn = 0 

Show that: 

(a) H'n = 2nHn−1 

(b) Hn+1 = 2ξHn − 2nHn−1

1 Answer

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Best answer

Express Hn in terms of a generating function T(ξ,s)

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