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in Physics by (70.0k points)

A 5 MeV proton moves vertically downward through a magnetic field of induction 1.5 weber/m2 pointing horizontally from south to north. The force acting on the proton, mass of proton = 1.6 × 10–27 kg. will be-

(A) 7.44 × 10–12

(B) 3.1 × 10–12

(C) 5 × 10–12

(D) 6 × 10–12 N

1 Answer

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Best answer

Correct option (A) 7.44 × 10–12 N

Explanation:

Kinetic energy of the proton = 1/2 mv2 = 5 meV

The magnetic field is horizontal from south to north and velocity vector v is vertically downward, i.e. angle between vector v and is vector B is 90º therefore force on proton

According to Fleming left had rule, the direction of force is horizontal from west to east.

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