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The work done in carrying a charge of 50μC from a point A to a point B in an electric field is 10 mJ. The potential difference (VB − VA) is :

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The work done in carrying a charge of 50μC from a point A to a point B in an electric field is 10 mJ. The potential difference (VB − VA) is : 

(a) − 200V 

(b) + 200V 

(c) − 2kV 

(d) + 2kV

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1 Answer

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Best answer

Correct option (b) + 200V

Explanation:

The work done in carrying a charge of 50 μC from A to B is given by 

W = charge × potential difference 

W = q × (VB − VA) 

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