Question

The capacity of the capacitors are shown in adjoining figure. The equivalent capacitance between the points A and B and the charge on the 6 μF capacitor will be :

(a) 15 μF, 90 μC 

(b) 6 μF, 180 μC 

(c) 15 μF, 270 μC 

(d) 27 μF, 540 μC

Answer 1

Correct option (b) 6 μF, 180 μC

Explanation:

The given circuit can be modified as The equivalent capacitance of C₂ and C₃ is

Since, C₁ and C′ are in series, therefore, charge on C₁ and C′ will be same

i.e. q = CAB × V

= 6 × 90 = 540 μC

Now the potential on 6 μF and 12 μF are same,

Hence, charge on 6 μF capacitor is

q₆ = 30 × 6 = 180 μC