C.V. Hammerhead
The hammerhead does not change internal energy i.e. same P,T
E2 – E1 = m(u2 – u1) + m(1/2V22 - 0) + mg (h2 - 0)
= 0 + [ 50 × (1/2) ×1502 + 50 × 32.174 × (-3)] / 32.174
= [562500 – 4826]/32.174
= 17 333 lbf-ft
= (17333/778 ) Btu
= 22.28 Btu