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Is the same time necessary for a cutter to travel a distance of 1 km upstream and back on a river (current velocity is equal to 2 km/hr) as on a lake (in still water) if the velocity of the cutter relative to the water is, in both cases, 8 km/hr? Solve the problem analytically and graphically.

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Answer: The time of travel on the river is 1.07 times that on the lake. 

Explanation:

The time of travel upstream on the river is t1 = S/(v2 —v1), where S = 1km, v1 = 2km/hr, v2 = 8km/hr. The time of travel downstream is t2 = S/(v2 + v1). 

The total time of travel on the river (there and back) is 

t = t1 + t2 = 2Sv2/(v22 — v21). 

The time of travel there and back on the lake is t3 = 2S/v2 . The ratio of the two times is

t/t3 = v22/(v22 - v21) = 1.07.

Figure represents a plot of the motion: I is the motion in still water, II is the motion in the river; t3 and t are the corresponding times in each case.

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