Answer: The time of travel on the river is 1.07 times that on the lake.
Explanation:
The time of travel upstream on the river is t1 = S/(v2 —v1), where S = 1km, v1 = 2km/hr, v2 = 8km/hr. The time of travel downstream is t2 = S/(v2 + v1).
The total time of travel on the river (there and back) is
t = t1 + t2 = 2Sv2/(v22 — v21).
The time of travel there and back on the lake is t3 = 2S/v2 . The ratio of the two times is
t/t3 = v22/(v22 - v21) = 1.07.
Figure represents a plot of the motion: I is the motion in still water, II is the motion in the river; t3 and t are the corresponding times in each case.
