Question

In previous question if second pendulum bob is thrown at velocity v₂ at an angle β from mean position but on other side of mean position. Find the phase difference in the two SHM s no was shown in figure.

Answer 1

In this case still amplitudes of the two SHMs will remain same and are given by equation (1) and (2) but when we represent the two SHMs on their corresponding circular motions, the position of the particle in circular motion in second pendulum is now different as shown in figure. As shown in figure (a) and (b) the initial phases of the two pendulum bobs are

Asω for both SHM are same, their phase difference remains constant so it is given as