Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
625 views
in Physics by (72.0k points)

An old artillery gun not possessing an anti-recoil device, fires a cannon ball at an angle of 40° to the horizontal. The cannon ball has a mass of 10kg and an initial velocity of 200m/sec. What is the velocity of recoil of the gun if its mass is 500kg? Neglect friction.

1 Answer

+1 vote
by (68.8k points)
selected by
 
Best answer

Answer:

Explanation:

To determine the velocity of recoil of the gun it is necessary to take into account only the horizontal component of the projectile velocity, since the recoil due to the vertical component of this velocity will be absorbed by the reaction at the ground. the horizontal component of the velocity of the projectile is vx = v0cosα. According to the law of conservation of momentum, Mv1 = mvx, from which it follows that

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...