Question

If a circle passes through the point (a, b) and cuts the circle x² + y² = p² orthogonally, then the equation of the locus of its centre is
(a) 2ax + 2by – (a² – b² + p² ) = 0
(b) x² + y² – 3ax – 4by + (a² + b² – p² ) = 0
(c) 2ax + 2by – (a² + b² + p² ) = 0
(d) x² + y² – 2ax – 3by + (a² – b² – p² ) = 0.

Answer 1

The correct answer is: