Given,
let lz2/mz1 = iy
z2/z1 = iym/l
⇒|lambda z1+µz2/lamda z1-µz2|
dividing numerator and denominator by z1 we get
⇒|lambda(1)+µ(z2/z1) / lambda(1)-µ(z2/z1)|
we know that z2/z1 = imy/l
⇒|lambda+µ(imy/l) / lambda-µ(imy/l)|
we know that |x+iy| = root of (x2+y2)
⇒square root(lambda² + µ²y²/l² )/square root( lambda² + µ²y²/l²)
⇒1
hope this helps :)