Question

The equation of a straight line which cuts off an intercept of 5 units on negative direction of y-axis and makes an angle 120° with positive direction of x-axis is 

A. y + √3x + 5 = 0 

B. y − √3x + 5 = 0 

C. y + √3x − 5 = 0 

D. y − √3x − 5 = 0

Answer 1

Correct option  A. y + √3x + 5 = 0

Explanation:

Required equation of line is:

y + 5 = tan 120°x

Or y + 5 = -√3x

Or y + √3 x + 5 = 0