Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
16.3k views
in Gravitation by (55.7k points)
recategorized by

Two bodies of masses m and M are placed a distance d apart. The gravitational potential at the position where the gravitational field due to them is zero is V, then

(a) V = -G/d (m +M)

(b) V = -Gm/d

(c) V= -Gm/d 

(d) V = -G/d (√m+√m)2

1 Answer

+1 vote
by (57.8k points)
selected by
 
Best answer

Correct option (d) V = -G/d (√m+√m)2

Explanation

If P is the point of zero intensity, then 

Now potential at point P, 

Substituting the value of x and d – x we get 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...