Question

Two oxides of metal ‘M’ contain 27.6% and 30.0% of oxygen respectively. If the formula of the first oxide is M₃O_4, find that of the second.

(1) M₂O₃ 

(2) M₂O 

(3) MO₂

(4) M₃O₂

Answer 1

Correct option M₂O₃

Explanation:

 Let ‘x’ be the atomic wt. of metal M, for first oxide

(72.4/x : 27.6/16) = 3: 4 ⇒ M₃O₄

X = 56

For second oxide, 70/56: 30/16 = 2: 3 ⇒ M₂O₃.