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Let S = {1, 2, 3, ..., 9}. For k = 1, 2, ..., 5, let Nk be the number of subsets of S, each containing five elements out of which exactly k are odd. Then N1 + N2 + N3 + N4 + N5 =

(A) 210 

(B) 252

(C) 125 

(D) 126

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