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If the length of portion of normal intercepted between the curve & x-axis varies as the square of the ordinate, then the curve is

(a)   kx + √(1 - k2x2) = C .eky

(b)   ky + √(k2y2 - 1) = C .ekx

(c)   ky + √(k2x2 - 1) = Cexy

(d)   None of these

1 Answer

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Best answer

Correct option  (b)   ky + √(k2y2 - 1) = C .ekx

Explanation:

Normal is Y– y  = dx/dy(X - x)

Point on x-axis is(x + ydy/dx,0)

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