Correct option (d) 0.25 m, 1 m, 0.5 m
Explanation :
For point ‘P ’ 1/Vp - 1/3 = -1/1 ⇒ 1/Vp = -1 + 1/3
Vp = - 3/2 m
For point ‘Q ’ 1/Vp - 1/5 = -1/1 ⇒1/Vq = -1 + 1/5
Vq = -5/4
So Vp - VQ = 0.25m
Height of image of ‘P ’ ⇒ m = -v/u = h1/h0
= - (+3/2/+ 3) = h1/2m ⇒ h1 = - 1/2m
Height of image ‘Q’ ⇒ m = -(-5/4/5)
= h1/2m
h1 = 0.25m
So height of image of Q pace = 0.5m
Height of image of P pace = 1.0m