Question

A wire of length 2.50 m has a percentage strain of 0.012% when loaded with a tensile force. Determine the extension of the wire.

Answer 1

Original length of wire = 2.50 m = 2500 mm

and strain = 0.012/100 = 0.00012

Strain ε = extension x/original length L

hence, extension x = εL = (0.00012)(2500) 

= 0.30 mm