(i) tanφ = - (√3(W1 - W2))/(W1 + W2) = -(√3(782 - 1980))/(782 + 1980) = 0.75;
φ = 36.9°, cosφ = 0.8
(ii) 3 x 416 x IL x 0.8 = 2762, IL = 4.8A
(iii) Zph = Vph/Iph = (416√3)/4.8 = 50Ω; XC = Zphsinφ = 50 x 0.6 = 30Ω
Now, XC = 1/2πfC = 1/2φ x 50 x C = 106 x 10-6F