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A star-connected balanced load is supplied from a 3− φ balanced supply with a line voltage of 416 volts at a frequency of 50 Hz. Each phase of the load consists of a resistance and a capacitor joined in series and the reading on two wattmeters connected to measure the total power supplied are 782 W and 1980 W, both positive. Calculate (i) power factor of circuit, (ii) the line current, (iii) the capacitance of each capacitor

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(i) tanφ = - (√3(W1 - W2))/(W1 + W2) = -(√3(782 - 1980))/(782 + 1980) = 0.75;

φ = 36.9°, cosφ = 0.8

(ii) 3 x 416 x IL x 0.8 = 2762, IL = 4.8A

(iii) Zph = Vph/Iph = (416√3)/4.8 = 50Ω; XC = Zphsinφ = 50 x 0.6 = 30Ω

Now, XC = 1/2πfC = 1/2φ x 50 x C = 106 x 10-6F

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