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A simple pendulum of length l is made to oscillate with an amplitude of 45 degrees. The acceleration due to gravity is g. Let T0 = 2 π l/g. The lime period of oscillation of this pendulum will be 

(A) T0 irrespective of the amplitude. 

(B) slightly less than T0.

(C) slightly more than T0.

(D) dependent on whether it swings in a plane aligned with the north-south or cast-west directions.

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1 Answer

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by (323k points)

The correct option is (A)  T0 irrespective of the amplitude.

Explanation:

T0 = 2 π l/g

If θ is greater, then a < gθ 

Hence time-period T' > T0.

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