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in Co-ordinate geometry by (64.8k points)

Let PQR be a triangle of area ∆ with a = 2, b = 7/2  and c = 5/2, where a, b and c are lengths of the sides of the triangle opposite to the angle at P, Q and R respectively. Then (2sinP - sin2P)/(2sinP + sin2P) equals

(A) 3/4∆

(B) 45/4∆

(C) (3/4∆)2

(D) (45/4∆)2

1 Answer

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Best answer

Correct option (C) (3/4∆)2

Explanation:

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