Question

Calculate the standard enthalpy change for the reaction 

2C₈H₁₈(l) + 17O₂(g) → 16CO(g) + 18H₂O(l). 

Given:

2C₈H₁₈(l) + 25O₂(g) →16CO₂(g) + 18H₂O(l) ΔH° = –11,020 kJ/mol

2CO(g) + O₂(g) → 2CO₂₍g) ΔH° = –566.0 kJ/mol

(A) 10,450 kJ/mol

(B) 6,492 kJ/mol

(C) 15,550 kJ/mol

(D) –6,492 kJ/mol

(E) –10.450 kJ/mol

Answer 1

(D) –6,492 kJ/mol