Question

Find the range of the function

f(x) = sin^-1((cos²x + 1)/2)

Answer 1

Let g(x) = ((cos²x + 1)/2)

Thus, R_g = [1/2, 1]

Therefore,

R_f = [sin^-1(1/2), sin^-1(1)] = [π/6, π/6]