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in Mathematics by (53.3k points)

Prove that the locus of the midpoint of the portion of a normal to y2 = 4ax intercepted between the curve and the axis is another parabola

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Normal at P(at2, 2at) is

tx + y = 2at + at3

 Substituting y = 0 in the above equation, we have

x = 2a + at2

 Hence, the normal meets the axis at N(2a + at2,0). Let (α    β) be the midpoint of PN so that α = a + at2 and β = at. Therefore

Hence, the locus of the midpoint of PN is

y2 = a(x - a)

 which is a parabola.

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