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The line (x - 2)/3 = (y + 1)/4 = (z - 2)/1 meets the plane x − y + z = 5 at Q. If P is the point (−1, −5, −10), then the

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The line

(x - 2)/3 = (y + 1)/4 = (z - 2)/1

meets the plane x − y + z = 5 at Q. If P is the point (−1, −5, −10), then the distance PQ is 

(A) 10 

(B) 11 

(C) 13/2 

(D) 13 

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1 Answer

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by (57.6k points)

Correct option is (D) 13

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