Let P =(a secθ, a tanθ) so that M = (a sec θ, 0) and N = (0, a tanθ ). The tangent at P is
x secθ - y tan θ = a
so that the slope of the tangent at P is
sec θ/tan θ = cosec θ
Slope of MN is
-a tanθ/a sec θ = - sin θ
Now,
Slope of the tangent at P X Slope of MN = cosec θ x (- sin θ) = -1
Hence, the tangent at P is perpendicular to MN. Also d is the distance of O from the tangent at P which is given by