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JEE MAIN 2026 Crash Course
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1 Answer

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Best answer

∫ dx/1 + ex = ∫ e–x/(e–x + 1) dx 

Let e–x + 1 = t 

– e–x dx = dt 

= – ∫ dt/ t + 1 

= – log |t + 1| + c 

= – log |e –x + 1| + c

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