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in Mathematics by (53.3k points)

If the angle between the asymptotes of a hyperbola is π/3,  then the eccentricity of its conjugate hyperbola is .....

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let e' be the eccentricity of the conjugate hyperbola. Therefore

1/e2 + 1/e'2 = 1 

⇒ 1/e'2 = 1 - 3/4 = 1/4

Hence e' =2.

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