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+1 vote
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in Integrals calculus by (38.6k points)

Evaluate: ∫ dx/ (4x2 + 4x + 1) √(4x2 + 4x + 7)

1 Answer

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Best answer

Again, let 6t2 + 1 = v2

12t dt = 2v dv

tdt = (1/6) v dv 

= – (1/12) ∫ v dv/ v

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