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For reduction of ferric oxide by hydrogen, Fe2O3(S) + 3H2(g)→2Fe(s) +3H2O(l)

∆H°298 = -35.1 kJ.The reaction was found to be too exothermic to be convenient. It is desirable that ∆Ho should be at the most – 26kJ. At what temperature is it possible?

Cp[Fe2O3] = 104.5, Cp [Fe(s)] = 25.5,

Cp[H2(l)] = 75.3, Cp [H2(g)] = 28.9 (All in J/mol)

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Best answer

(9100/85.7) =  T–298

Tf = 404.18 K 

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