f = {(1, 1), (2, 3), (0, –1), (–1, –3)} and f(x) = ax + b

(1, 1) ∈ f ⇒

f(1) = 1

⇒ a × 1 + b = 1

⇒ a + b = 1 (0, –1) ∈ f

⇒ f(0) = –1 ⇒ a × 0 + b = –1

⇒ b = –1

On substituting b = –1 in a + b = 1,

We obtain a + (–1) = 1 ⇒ a = 1 + 1 = 2.

Thus, the respective values of a and b are 2 and –1.