Given f(x) = (x – a)m(x – b)n
As we know that every polynomial function is continuous and differentiable everywhere.
So, f(x) is continuous and differentiable on the given indicated interval.
Also, f(a) = 0 = f(b).
Thus, all the conditions of Rolle’s theorem are satisfied.
Now, we have to show that there exist a point c in (a, b) such that f'(c) = 0
So,
f'(x) = m(x – a)m–1 (x – b)n + n(x – a)m(x – b)n–1
f'(x) = (x – a)m–1 (x – b)n–1 (m(x – b) + n(x – a))
Now, f'(c) gives c = a, c = b and
⇒ (m(c – b) + n(c – a)) = 0
⇒ c = (mb + na)/(m + n) ∈(a, b)
Hence, Rolle’s theorem is verified.