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Prove that ∫ (sin nθ/sinθ)2 dθ for x ∈ [0,π/2] = nπ, where n ∈ W

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Prove that ∫ (sin nθ/sinθ)2 dθ for x ∈ [0,π/2] = nπ, where n ∈ W

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Best answer

Let

Now,

= ∫ (sin(2n – 1) θ/sinθ) dθ for x ∈ [0,π/2]

= π

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