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in Mathematics by (48.5k points)

If S = a, b, b, c, c, c, d, d, d, d, …..z,z,z.

Find the number of terms in the above series:

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S consists one a, two b’s, three c’s and so on. 

So total number of terms = 1 + 2 + 3 + …..+ 26 = 26/2(1+26) =13 x 27 = 351.

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