Given curves are ay + x2 = 7 and y = x3 ...(i)
⇒ a(dy/dx) + 2x = 0, dy/dx = 3x2
⇒ dy/dx = – 2x/a , dy/dx = 3x2
Since the curves cut orthogonally, so
⇒ – 2x/a × 3x2 = –1
⇒ a = 6x3 ...(ii)
On solving (i) and (ii), we get,
6x6 + x2 = 7
⇒ x = 1
Hence, the value of a is 6 .