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in Limit, continuity and differentiability by (54.8k points)

If the curves ay + x2 = 7 and y = x3 cut each other orthogonally at a point, find a.

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Given curves are ay + x2 = 7 and y = x3 ...(i)

 a(dy/dx)  + 2x = 0, dy/dx = 3x2

⇒ dy/dx = – 2x/a , dy/dx = 3x2

Since the curves cut orthogonally, so

 – 2x/a × 3x2 = –1

 a = 6x3 ...(ii)

On solving (i) and (ii), we get,

6x6 + x2 = 7

 x = 1

Hence, the value of a is 6 .

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