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A particle of mass m1 makes an elastic, one-dimensional collision with a stationary particle of mass m2. What fraction of the kinetic energy of m1 is carried away by m2?

(a) m1 /m2

(b) m3 /m1

(c) 2m1m2 / (m1 + m2)2

(d) 4m1m2 / (m1 + m2)2

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Correct answer is: (d) 4m1m2 / (m1 + m2)2

Let v1 and v2 be the velocities of m1 and m2 after collision. Then,

m1u = m1v1 + m2v2 and v2 - v1 = -1(0 - u)

Find v2 in terms of u. The required fraction is

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