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+1 vote
18.1k views
in Sets, relations and functions by (53.5k points)

If R  = {(x,y)| x, y  Z, x2 +y2 ≤ 4} is a relation in Z, then domain of R is 

(A)  {0, 1, 2}

(B)  {0, –1, –2}

(C)  {–2, –1, 0, 1, 2}

(D)  None of these

1 Answer

+1 vote
by (53.3k points)
selected by
 
Best answer

Correct option  (C) {–2, –1, 0, 1, 2}

Explanation :

As R = ∈ {(x,y)| x, y ∈ Z, } x2 + y2 ≤ 4

Therefore, R = {(-2,0),(-1,0) ,(-1,1),(0,-1),(0,2),(0,-2)} Hence, domain of R = {-2,-1,0,1,2}.

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