Correct option (A) → (q), (B) → (q), (C) → (q), (D) → (r)
(A) Fundamental period of sin-1 (sin kx) is 2π/|k| = π/2.
That is, |k| = 4
⇒ K = ±4
(B) Domain of tan–1 x is R, domain of sin–1x is [–1, 1], domain of sec–1x is (–∞, –1] ∪ [1, ∞). Therefore, domain of f(x) is {–1, 1}
(C) π is a period of sin x ⋅ cosec x
Therefore, π x 2/π is a period of sin πx/2. cosec π x/2
That is, 2 is a period of sin πx/2 cosec πx/2
