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Show that sin(45° + A)sin(45° - A) = 1/2 cos 2A

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asked Dec 7, 2019 in Trigonometry by RiteshBharti (53.5k points)

Show that sin(45° + A)sin(45° - A) = 1/2 cos 2A

trigonometric identities
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1 Answer

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answered Dec 7, 2019 by SudhirMandal (53.4k points)
selected Dec 7, 2019 by RiteshBharti

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sin(45° + A)sin(45° - A) = 1/2 {[cos (2A) - cos(90°)]} = 1/2cos(2A)

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Show that sin(45° + A)sin(45° - A) = 1/2 cos 2A

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