Question

If f(x) = {(-x², when x≤ 0), (5x - 4, when 0 < x ≤ 1), (4x² - 3x, when 1 < 2), (3x + 4, when x ≥ 2), then

(A) f(x) is continuous at x = 0 

(B) f(x) is continuous at x = 2 

(C) f(x) is discontinuous at x = 1 

(D) None of these

Answer 1

Answer is (B) f(x) is continuous at x = 2

 

f(x) discontinuous at x = 0.

Hence, f(x) is continuous at x = 1.

Hence, f(x) is continuous at x = 2