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The range of y = sin^3x − 6sin^2x + 11sinx − 6 is

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The range of y = sin3x − 6sin2x + 11sinx − 6 is

(A)  [−24, 2] 

(B)  [−24, 0] 

(C)  [0, 24] 

(D)  None of these

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1 Answer

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Best answer

Correct option  (B) [−24, 0]

Put sinx = t

 y = t3 – 6t2 + 11t – 6, – 1 ≤ t ≤ 1

f(–1) = – 24, f(1) = 0

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