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in Physics by (51.2k points)

The emf of a cell is  and its internal resistance is r. Its terminals are connected to a resistance R. The potential difference between the terminals is 1.6 V for R = 4 Ω, and 1.8 V for R = 9 Ω. Then,

(a)  = 1 V, r = 1Ω 

(b)  = 2 V, r = 1Ω 

(c)  = 2 V, r = 2Ω 

(d)  = 2.5 V, r = 0.5Ω

1 Answer

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by (50.3k points)
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Best answer

Correct Answer is: (b)  = 2 V, r = 1Ω 

Current in the circuit = i = ℰ / R + r.

p.d. across cell = p.d. across R = iR = R/R + r.

Set up two equations with the given data and solve for , r.

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