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d/dx[cos(1 - x^2)^2] is equal to (A) - 2x(1 - x^2)sin(1 - x^2)^2

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d/dx[cos(1 - x2)2] is equal to

(A) - 2x(1 - x2)sin(1 - x2)2

(B) - 4x(1 - x2)sin(1 - x2)2

(C) 4x(1 - x2)sin(1 - x2)2

(D) - 2(1 - x2)sin(1 - x2)2

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1 Answer

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Answer is (C) 4x(1 - x2)sin(1 - x2)2

 

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