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Find the number of triangles ABC that can be formed with a = 3, b = 8 and sinA = 5/3.

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in Trigonometry by (53.3k points)

Find the number of triangles ABC that can be formed with a = 3, b = 8 and sinA = 5/3.

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Given a = 3, b = 8 and sinA = 5/13.  Therefore

b sin A = 8 x (5/13) = 40/13 >(= 3)

Thus, in this case no triangle is possible.

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