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A cubic f(x) vanishes at x = −2 and has relative minimum/ maximum at x = −1 and x = 1/3. If ∫f(x)dx for x ∈ [-1, 1] = 14/3, the cubic f(x) = λ1x3λ2x2 − x + 2, then find (λ1λ2).

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x = − 1 and x = 1/3 are roots of f′(x) = 0. Therefore,

f′(x) = a(3x − 1) (x + 1) = a(3x2 + 2x − 1)

⇒ f(x) = a(x3 + x2 − x + b) f(−2) = 0

⇒ b = 2 ⇒ f(x) = a(x3 + x2 − x + 2)

Therefore, 

f(x) = x3 + x2 − x + 2

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