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0 votes
10.5k views
in Trigonometry by (53.5k points)

Two circles C1 and C2 intersect at two distinct points P and Q in a plane. Let a line passing through P meet the circles C1 and C2 in A and B, respectively. Let Y be the mid-point of AB and QY meet the circles C1 and C2 in X and Z, respectively. Then

(A)  Y is the mid-point of XZ

(B)  XY/XZ = 2/1

(C)  YX = YZ

(D)  XY + YZ = 3Y

1 Answer

+1 vote
by (53.3k points)
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Best answer

Correct option  (A), (C)

YP . YB = YZ . YQ and YA . YP = YX . YQ

But YA = YB. Hence, YX = YZ

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